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1312111002433 = 71173233430173
BaseRepresentation
bin10011000101111111111…
…010010000001101000001
311122102210021100010021211
4103011333322100031001
5132444200404034213
62442435300250121
7163540222333360
oct23057772201501
94572707303254
101312111002433
114665104aa610
121923673a0941
139696825567a
1447713c1d7d7
15241e72c053d
hex1317fe90341

1312111002433 has 16 divisors (see below), whose sum is σ = 1658287956096. Its totient is φ = 1008418343040.

The previous prime is 1312111002421. The next prime is 1312111002479. The reversal of 1312111002433 is 3342001112131.

It is a cyclic number.

It is not a de Polignac number, because 1312111002433 - 25 = 1312111002401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312111005433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 116709466 + ... + 116720707.

It is an arithmetic number, because the mean of its divisors is an integer number (103642997256).

Almost surely, 21312111002433 is an apocalyptic number.

It is an amenable number.

1312111002433 is a deficient number, since it is larger than the sum of its proper divisors (346176953663).

1312111002433 is a wasteful number, since it uses less digits than its factorization.

1312111002433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233430264.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1312111002433 its reverse (3342001112131), we get a palindrome (4654112114564).

The spelling of 1312111002433 in words is "one trillion, three hundred twelve billion, one hundred eleven million, two thousand, four hundred thirty-three".

Divisors: 1 7 11 73 77 511 803 5621 233430173 1634011211 2567731903 17040402629 17974123321 119282818403 187444428919 1312111002433