131211140201 has 4 divisors (see below), whose sum is σ = 131211917904. Its totient is φ = 131210362500.

The previous prime is 131211140197. The next prime is 131211140219. The reversal of 131211140201 is 102041112131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 131211140201 - 2² = 131211140197 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 131211140201.

It is not an unprimeable number, because it can be changed into a prime (131211146201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17675 + ... + 512576.

It is an arithmetic number, because the mean of its divisors is an integer number (32802979476).

Almost surely, 2^131211140201 is an apocalyptic number.

It is an amenable number.

131211140201 is a deficient number, since it is larger than the sum of its proper divisors (777703).

131211140201 is an equidigital number, since it uses as much as digits as its factorization.

131211140201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 777702.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 131211140201 its reverse (102041112131), we get a palindrome (233252252332).

The spelling of 131211140201 in words is "one hundred thirty-one billion, two hundred eleven million, one hundred forty thousand, two hundred one".