Base | Representation |
---|---|
bin | 10011000110000000000… |
… | …011001000110010000011 |
3 | 11122102210102201102221022 |
4 | 103012000003020302003 |
5 | 132444202003100311 |
6 | 2442435422220055 |
7 | 163540251203225 |
oct | 23060003106203 |
9 | 4572712642838 |
10 | 1312113331331 |
11 | 466511850320 |
12 | 19236812462b |
13 | 9696888c70a |
14 | 47714268415 |
15 | 241e75d05db |
hex | 131800c8c83 |
1312113331331 has 4 divisors (see below), whose sum is σ = 1431396361464. Its totient is φ = 1192830301200.
The previous prime is 1312113331327. The next prime is 1312113331351. The reversal of 1312113331331 is 1331333112131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312113331331 - 22 = 1312113331327 is a prime.
It is a super-2 number, since 2×13121133313312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1312113331331.
It is not an unprimeable number, because it can be changed into a prime (1312113331351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59641515050 + ... + 59641515071.
It is an arithmetic number, because the mean of its divisors is an integer number (357849090366).
Almost surely, 21312113331331 is an apocalyptic number.
1312113331331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1312113331331 is a deficient number, since it is larger than the sum of its proper divisors (119283030133).
1312113331331 is a wasteful number, since it uses less digits than its factorization.
1312113331331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 119283030132.
The product of its digits is 1458, while the sum is 26.
Adding to 1312113331331 its reverse (1331333112131), we get a palindrome (2643446443462).
The spelling of 1312113331331 in words is "one trillion, three hundred twelve billion, one hundred thirteen million, three hundred thirty-one thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •