13121143413403 has 4 divisors (see below), whose sum is σ = 13121179230880. Its totient is φ = 13121107595928.

The previous prime is 13121143413361. The next prime is 13121143413419. The reversal of 13121143413403 is 30431434112131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13121143413403 - 2¹³ = 13121143405211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13121143413463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17353500 + ... + 18093817.

It is an arithmetic number, because the mean of its divisors is an integer number (3280294807720).

Almost surely, 2^{13121143413403} is an apocalyptic number.

13121143413403 is a deficient number, since it is larger than the sum of its proper divisors (35817477).

13121143413403 is an equidigital number, since it uses as much as digits as its factorization.

13121143413403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35817476.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 13121143413403 its reverse (30431434112131), we get a palindrome (43552577525534).

The spelling of 13121143413403 in words is "thirteen trillion, one hundred twenty-one billion, one hundred forty-three million, four hundred thirteen thousand, four hundred three".