131211441042041 has 4 divisors (see below), whose sum is σ = 131211468815232. Its totient is φ = 131211413268852.

The previous prime is 131211441041983. The next prime is 131211441042047. The reversal of 131211441042041 is 140240144112131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131211441042041 - 2²² = 131211436847737 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131211441041995 and 131211441042013.

It is not an unprimeable number, because it can be changed into a prime (131211441042047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4832045 + ... + 16904778.

It is an arithmetic number, because the mean of its divisors is an integer number (32802867203808).

Almost surely, 2^{131211441042041} is an apocalyptic number.

It is an amenable number.

131211441042041 is a deficient number, since it is larger than the sum of its proper divisors (27773191).

131211441042041 is an equidigital number, since it uses as much as digits as its factorization.

131211441042041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27773190.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 131211441042041 its reverse (140240144112131), we get a palindrome (271451585154172).

The spelling of 131211441042041 in words is "one hundred thirty-one trillion, two hundred eleven billion, four hundred forty-one million, forty-two thousand, forty-one".