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1312122254651 = 13100932481127
BaseRepresentation
bin10011000110000000100…
…101001011010100111011
311122102211001111210102122
4103012000211023110323
5132444211244122101
62442440341351455
7163540420066565
oct23060045132473
94572731453378
101312122254651
1146651689556a
1219236b10858b
139696a6951a0
144771550c335
15241e829451b
hex1318094b53b

1312122254651 has 4 divisors (see below), whose sum is σ = 1413054735792. Its totient is φ = 1211189773512.

The previous prime is 1312122254593. The next prime is 1312122254693. The reversal of 1312122254651 is 1564522212131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312122254651 - 222 = 1312118060347 is a prime.

It is a super-2 number, since 2×13121222546512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312122254851) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50466240551 + ... + 50466240576.

It is an arithmetic number, because the mean of its divisors is an integer number (353263683948).

Almost surely, 21312122254651 is an apocalyptic number.

1312122254651 is a deficient number, since it is larger than the sum of its proper divisors (100932481141).

1312122254651 is a wasteful number, since it uses less digits than its factorization.

1312122254651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100932481140.

The product of its digits is 28800, while the sum is 35.

Adding to 1312122254651 its reverse (1564522212131), we get a palindrome (2876644466782).

The spelling of 1312122254651 in words is "one trillion, three hundred twelve billion, one hundred twenty-two million, two hundred fifty-four thousand, six hundred fifty-one".

Divisors: 1 13 100932481127 1312122254651