Base | Representation |
---|---|
bin | 1011111011110000011001… |
… | …0000101000000111100001 |
3 | 1201110101012002100021010001 |
4 | 2332330012100220013201 |
5 | 3204434234402024301 |
6 | 43523450534340001 |
7 | 2522656212503002 |
oct | 276740620500741 |
9 | 51411162307101 |
10 | 13121230111201 |
11 | 41a9756367643 |
12 | 157ab954ba601 |
13 | 74243297a724 |
14 | 3350dc8991a9 |
15 | 17b4a7624c01 |
hex | bef064281e1 |
13121230111201 has 4 divisors (see below), whose sum is σ = 13426374997552. Its totient is φ = 12816085224852.
The previous prime is 13121230111189. The next prime is 13121230111207. The reversal of 13121230111201 is 10211103212131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13121230111201 - 233 = 13112640176609 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13121230111207) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 152572443111 + ... + 152572443196.
It is an arithmetic number, because the mean of its divisors is an integer number (3356593749388).
Almost surely, 213121230111201 is an apocalyptic number.
It is an amenable number.
13121230111201 is a deficient number, since it is larger than the sum of its proper divisors (305144886351).
13121230111201 is an equidigital number, since it uses as much as digits as its factorization.
13121230111201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 305144886350.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 13121230111201 its reverse (10211103212131), we get a palindrome (23332333323332).
The spelling of 13121230111201 in words is "thirteen trillion, one hundred twenty-one billion, two hundred thirty million, one hundred eleven thousand, two hundred one".
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