Base | Representation |
---|---|
bin | 11101110101011001101000… |
… | …100001000110101011111011 |
3 | 122012120211200212210102210200 |
4 | 131311121220201012223323 |
5 | 114144243213111321103 |
6 | 1143022231100013243 |
7 | 36431553366043311 |
oct | 3565315041065373 |
9 | 565524625712720 |
10 | 131213004401403 |
11 | 388991392a55a1 |
12 | 12871b61831223 |
13 | 582a444123062 |
14 | 2458a5987a0b1 |
15 | 1028240ca50a3 |
hex | 775668846afb |
131213004401403 has 12 divisors (see below), whose sum is σ = 189564236665440. Its totient is φ = 87459486381936.
The previous prime is 131213004401329. The next prime is 131213004401419. The reversal of 131213004401403 is 304104400312131.
131213004401403 is a `hidden beast` number, since 1 + 3 + 1 + 213 + 0 + 0 + 4 + 40 + 1 + 403 = 666.
It is not a de Polignac number, because 131213004401403 - 238 = 130938126494459 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131213004401473) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1320771376 + ... + 1320870717.
It is an arithmetic number, because the mean of its divisors is an integer number (15797019722120).
Almost surely, 2131213004401403 is an apocalyptic number.
131213004401403 is a deficient number, since it is larger than the sum of its proper divisors (58351232264037).
131213004401403 is a wasteful number, since it uses less digits than its factorization.
131213004401403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2641647618 (or 2641647615 counting only the distinct ones).
The product of its (nonzero) digits is 3456, while the sum is 27.
Adding to 131213004401403 its reverse (304104400312131), we get a palindrome (435317404713534).
The spelling of 131213004401403 in words is "one hundred thirty-one trillion, two hundred thirteen billion, four million, four hundred one thousand, four hundred three".
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