Search a number
-
+
131213113003 = 718744730429
BaseRepresentation
bin111101000110011101…
…0010011011010101011
3110112200110121202211001
41322030322103122223
54122211024104003
6140140052215431
712323404025650
oct1721472233253
9415613552731
10131213113003
1150713421965
122151b00a577
13c4b130a78b
1464ca64dc27
15362e5de61d
hex1e8ce936ab

131213113003 has 4 divisors (see below), whose sum is σ = 149957843440. Its totient is φ = 112468382568.

The previous prime is 131213113001. The next prime is 131213113019. The reversal of 131213113003 is 300311312131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 300311312131 = 677443591303.

It is a cyclic number.

It is not a de Polignac number, because 131213113003 - 21 = 131213113001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131213113001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9372365208 + ... + 9372365221.

It is an arithmetic number, because the mean of its divisors is an integer number (37489460860).

Almost surely, 2131213113003 is an apocalyptic number.

131213113003 is a deficient number, since it is larger than the sum of its proper divisors (18744730437).

131213113003 is an equidigital number, since it uses as much as digits as its factorization.

131213113003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18744730436.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 131213113003 its reverse (300311312131), we get a palindrome (431524425134).

The spelling of 131213113003 in words is "one hundred thirty-one billion, two hundred thirteen million, one hundred thirteen thousand, three".

Divisors: 1 7 18744730429 131213113003