Base | Representation |
---|---|
bin | 111101000110011101… |
… | …0101001011010111001 |
3 | 110112200110210100110001 |
4 | 1322030322221122321 |
5 | 4122211040000004 |
6 | 140140054153001 |
7 | 12323404552501 |
oct | 1721472513271 |
9 | 415613710401 |
10 | 131213203129 |
11 | 50713483648 |
12 | 2151b052761 |
13 | c4b133c7c8 |
14 | 64ca674a01 |
15 | 362e60b1a4 |
hex | 1e8cea96b9 |
131213203129 has 4 divisors (see below), whose sum is σ = 131278452880. Its totient is φ = 131147953380.
The previous prime is 131213203109. The next prime is 131213203151. The reversal of 131213203129 is 921302312131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131213203129 - 25 = 131213203097 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131213203097 and 131213203106.
It is not an unprimeable number, because it can be changed into a prime (131213203109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32621859 + ... + 32625880.
It is an arithmetic number, because the mean of its divisors is an integer number (32819613220).
Almost surely, 2131213203129 is an apocalyptic number.
It is an amenable number.
131213203129 is a deficient number, since it is larger than the sum of its proper divisors (65249751).
131213203129 is an equidigital number, since it uses as much as digits as its factorization.
131213203129 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65249750.
The product of its (nonzero) digits is 1944, while the sum is 28.
The spelling of 131213203129 in words is "one hundred thirty-one billion, two hundred thirteen million, two hundred three thousand, one hundred twenty-nine".
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