Base | Representation |
---|---|
bin | 1011111011110001000001… |
… | …1101010100010010010001 |
3 | 1201110101122000021222112122 |
4 | 2332330100131110102101 |
5 | 3204440112202210001 |
6 | 43523515525504025 |
7 | 2522663361016220 |
oct | 276742035242221 |
9 | 51411560258478 |
10 | 13121401210001 |
11 | 41a98339aa707 |
12 | 157b022872015 |
13 | 74245c255c16 |
14 | 3351174b6cb7 |
15 | 17b4b7670b1b |
hex | bef10754491 |
13121401210001 has 8 divisors (see below), whose sum is σ = 15034436938560. Its totient is φ = 11218002941808.
The previous prime is 13121401209967. The next prime is 13121401210019. The reversal of 13121401210001 is 10001210412131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13121401210001 - 26 = 13121401209937 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13121401210081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2409362171 + ... + 2409367616.
It is an arithmetic number, because the mean of its divisors is an integer number (1879304617320).
Almost surely, 213121401210001 is an apocalyptic number.
It is an amenable number.
13121401210001 is a deficient number, since it is larger than the sum of its proper divisors (1913035728559).
13121401210001 is an equidigital number, since it uses as much as digits as its factorization.
13121401210001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4818730183.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 13121401210001 its reverse (10001210412131), we get a palindrome (23122611622132).
The spelling of 13121401210001 in words is "thirteen trillion, one hundred twenty-one billion, four hundred one million, two hundred ten thousand, one".
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