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13121402011 = 61215104951
BaseRepresentation
bin11000011100001100…
…01011010010011011
31020212110020021201021
430032012023102123
5203333034331021
610010005103311
7643106035234
oct141606132233
936773207637
1013121402011
1156237645a3
1226623b7b37
131311599b03
148c692c08b
1551be32c41
hex30e18b49b

13121402011 has 4 divisors (see below), whose sum is σ = 13336507024. Its totient is φ = 12906297000.

The previous prime is 13121401963. The next prime is 13121402053. The reversal of 13121402011 is 11020412131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13121402011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13121402711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107552415 + ... + 107552536.

It is an arithmetic number, because the mean of its divisors is an integer number (3334126756).

Almost surely, 213121402011 is an apocalyptic number.

13121402011 is a deficient number, since it is larger than the sum of its proper divisors (215105013).

13121402011 is an equidigital number, since it uses as much as digits as its factorization.

13121402011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215105012.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13121402011 its reverse (11020412131), we get a palindrome (24141814142).

The spelling of 13121402011 in words is "thirteen billion, one hundred twenty-one million, four hundred two thousand, eleven".

Divisors: 1 61 215104951 13121402011