13121420441 has 4 divisors (see below), whose sum is σ = 13125372432. Its totient is φ = 13117468452.

The previous prime is 13121420413. The next prime is 13121420447. The reversal of 13121420441 is 14402412131.

13121420441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13121420441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13121420447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1971011 + ... + 1977656.

It is an arithmetic number, because the mean of its divisors is an integer number (3281343108).

Almost surely, 2^13121420441 is an apocalyptic number.

It is an amenable number.

13121420441 is a deficient number, since it is larger than the sum of its proper divisors (3951991).

13121420441 is an equidigital number, since it uses as much as digits as its factorization.

13121420441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3951990.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13121420441 its reverse (14402412131), we get a palindrome (27523832572).

The spelling of 13121420441 in words is "thirteen billion, one hundred twenty-one million, four hundred twenty thousand, four hundred forty-one".