131220000011 has 4 divisors (see below), whose sum is σ = 131220791592. Its totient is φ = 131219208432.

The previous prime is 131219999983. The next prime is 131220000017. The reversal of 131220000011 is 110000022131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131220000011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131219999947 and 131220000001.

It is not an unprimeable number, because it can be changed into a prime (131220000017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41306 + ... + 513951.

It is an arithmetic number, because the mean of its divisors is an integer number (32805197898).

Almost surely, 2^131220000011 is an apocalyptic number.

131220000011 is a deficient number, since it is larger than the sum of its proper divisors (791581).

131220000011 is an equidigital number, since it uses as much as digits as its factorization.

131220000011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 791580.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 131220000011 its reverse (110000022131), we get a palindrome (241220022142).

The spelling of 131220000011 in words is "one hundred thirty-one billion, two hundred twenty million, eleven", and thus it is an aban number.