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1312200110003 = 6192119870937
BaseRepresentation
bin10011000110000101001…
…110001010111110110011
311122110000111000020220012
4103012011032022332303
5132444341212010003
62442452202205135
7163542353621246
oct23060516127663
94573014006805
101312200110003
11466556831432
121923911b37ab
1396980854343
14477219b725d
15242000228d8
hex1318538afb3

1312200110003 has 4 divisors (see below), whose sum is σ = 1314319981560. Its totient is φ = 1310080238448.

The previous prime is 1312200109981. The next prime is 1312200110009. The reversal of 1312200110003 is 3000110022131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1312200110003 - 230 = 1311126368179 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1312200110003.

It is not an unprimeable number, because it can be changed into a prime (1312200110009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1059934850 + ... + 1059936087.

It is an arithmetic number, because the mean of its divisors is an integer number (328579995390).

Almost surely, 21312200110003 is an apocalyptic number.

1312200110003 is a deficient number, since it is larger than the sum of its proper divisors (2119871557).

1312200110003 is an equidigital number, since it uses as much as digits as its factorization.

1312200110003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2119871556.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 1312200110003 its reverse (3000110022131), we get a palindrome (4312310132134).

The spelling of 1312200110003 in words is "one trillion, three hundred twelve billion, two hundred million, one hundred ten thousand, three".

Divisors: 1 619 2119870937 1312200110003