Base | Representation |
---|---|
bin | 11101110101100000010001… |
… | …011011101111001101000011 |
3 | 122012121112002201002120201112 |
4 | 131311200101123233031003 |
5 | 114144402313111430144 |
6 | 1143025410321153535 |
7 | 36432225141553214 |
oct | 3565402133571503 |
9 | 565545081076645 |
10 | 131220133311299 |
11 | 388a116739706a |
12 | 1287341118b8ab |
13 | 582b00c052536 |
14 | 245913459140b |
15 | 102850ba8499e |
hex | 7758116ef343 |
131220133311299 has 4 divisors (see below), whose sum is σ = 131229508200864. Its totient is φ = 131210758421736.
The previous prime is 131220133311259. The next prime is 131220133311317. The reversal of 131220133311299 is 992113331022131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131220133311299 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131220133311229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4687423787 + ... + 4687451780.
It is an arithmetic number, because the mean of its divisors is an integer number (32807377050216).
Almost surely, 2131220133311299 is an apocalyptic number.
131220133311299 is a deficient number, since it is larger than the sum of its proper divisors (9374889565).
131220133311299 is an equidigital number, since it uses as much as digits as its factorization.
131220133311299 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9374889564.
The product of its (nonzero) digits is 52488, while the sum is 41.
The spelling of 131220133311299 in words is "one hundred thirty-one trillion, two hundred twenty billion, one hundred thirty-three million, three hundred eleven thousand, two hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •