Base | Representation |
---|---|
bin | 11000011100010001… |
… | …00101000110001011 |
3 | 1020212111102021220121 |
4 | 30032020211012023 |
5 | 203333220011021 |
6 | 10010030404111 |
7 | 643114301044 |
oct | 141610450613 |
9 | 36774367817 |
10 | 13122032011 |
11 | 5624054960 |
12 | 2662660637 |
13 | 131175a7aa |
14 | 8c6a538cb |
15 | 51c009741 |
hex | 30e22518b |
13122032011 has 4 divisors (see below), whose sum is σ = 14314944024. Its totient is φ = 11929120000.
The previous prime is 13122031987. The next prime is 13122032017. The reversal of 13122032011 is 11023022131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11023022131 = 11 ⋅1002092921.
It is a cyclic number.
It is not a de Polignac number, because 13122032011 - 215 = 13121999243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13122032017) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596455990 + ... + 596456011.
It is an arithmetic number, because the mean of its divisors is an integer number (3578736006).
Almost surely, 213122032011 is an apocalyptic number.
13122032011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13122032011 is a deficient number, since it is larger than the sum of its proper divisors (1192912013).
13122032011 is a wasteful number, since it uses less digits than its factorization.
13122032011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1192912012.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 13122032011 its reverse (11023022131), we get a palindrome (24145054142).
The spelling of 13122032011 in words is "thirteen billion, one hundred twenty-two million, thirty-two thousand, eleven".
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