Search a number
-
+
1312222300001 = 1969064331579
BaseRepresentation
bin10011000110000110100…
…010110100011101100001
311122110002000202121211222
4103012012202310131201
5132444412402100001
62442454313544425
7163543043341154
oct23060642643541
94573060677758
101312222300001
11466568308078
12192398715115
1396985323512
1447724911c9b
1524201e5761b
hex131868b4761

1312222300001 has 4 divisors (see below), whose sum is σ = 1381286631600. Its totient is φ = 1243157968404.

The previous prime is 1312222299961. The next prime is 1312222300031. The reversal of 1312222300001 is 1000032222131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1312222300001 - 230 = 1311148558177 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1312222300031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34532165771 + ... + 34532165808.

It is an arithmetic number, because the mean of its divisors is an integer number (345321657900).

Almost surely, 21312222300001 is an apocalyptic number.

It is an amenable number.

1312222300001 is a deficient number, since it is larger than the sum of its proper divisors (69064331599).

1312222300001 is an equidigital number, since it uses as much as digits as its factorization.

1312222300001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69064331598.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1312222300001 its reverse (1000032222131), we get a palindrome (2312254522132).

The spelling of 1312222300001 in words is "one trillion, three hundred twelve billion, two hundred twenty-two million, three hundred thousand, one".

Divisors: 1 19 69064331579 1312222300001