Base | Representation |
---|---|
bin | 1011111011110100011001… |
… | …0110001100010100100011 |
3 | 1201110110222000112010101011 |
4 | 2332331012112030110203 |
5 | 3204443440124441120 |
6 | 43524145343521351 |
7 | 2523024646531213 |
oct | 276750626142443 |
9 | 51413860463334 |
10 | 13122305312035 |
11 | 41aa158283977 |
12 | 157b2355b9257 |
13 | 74257465773a |
14 | 3351a15c0243 |
15 | 17b51bc0cc5a |
hex | bef4658c523 |
13122305312035 has 16 divisors (see below), whose sum is σ = 15812834571072. Its totient is φ = 10453802803200.
The previous prime is 13122305312027. The next prime is 13122305312147. The reversal of 13122305312035 is 53021350322131.
It is not a de Polignac number, because 13122305312035 - 23 = 13122305312027 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13122305311988 and 13122305312006.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27139162 + ... + 27618448.
It is an arithmetic number, because the mean of its divisors is an integer number (988302160692).
Almost surely, 213122305312035 is an apocalyptic number.
13122305312035 is a deficient number, since it is larger than the sum of its proper divisors (2690529259037).
13122305312035 is a wasteful number, since it uses less digits than its factorization.
13122305312035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 502254.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 13122305312035 its reverse (53021350322131), we get a palindrome (66143655634166).
The spelling of 13122305312035 in words is "thirteen trillion, one hundred twenty-two billion, three hundred five million, three hundred twelve thousand, thirty-five".
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