Base | Representation |
---|---|
bin | 10011000110000111000… |
… | …111110100111100110011 |
3 | 11122110002201000111120111 |
4 | 103012013013310330303 |
5 | 132444422343020311 |
6 | 2442455301522151 |
7 | 163543221655006 |
oct | 23060707647463 |
9 | 4573081014514 |
10 | 1312232001331 |
11 | 4665728338a9 |
12 | 19239ba13357 |
13 | 9698733c154 |
14 | 47725d1953d |
15 | 24202c21d21 |
hex | 131871f4f33 |
1312232001331 has 4 divisors (see below), whose sum is σ = 1312235184664. Its totient is φ = 1312228818000.
The previous prime is 1312232001293. The next prime is 1312232001347. The reversal of 1312232001331 is 1331002322131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312232001331 - 27 = 1312232001203 is a prime.
It is a super-2 number, since 2×13122320013312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312239001331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 861765 + ... + 1834966.
It is an arithmetic number, because the mean of its divisors is an integer number (328058796166).
Almost surely, 21312232001331 is an apocalyptic number.
1312232001331 is a deficient number, since it is larger than the sum of its proper divisors (3183333).
1312232001331 is an equidigital number, since it uses as much as digits as its factorization.
1312232001331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3183332.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1312232001331 its reverse (1331002322131), we get a palindrome (2643234323462).
The spelling of 1312232001331 in words is "one trillion, three hundred twelve billion, two hundred thirty-two million, one thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •