Base | Representation |
---|---|
bin | 10011000110000111000… |
… | …111110111110100111001 |
3 | 11122110002201001002201212 |
4 | 103012013013313310321 |
5 | 132444422343404423 |
6 | 2442455302052505 |
7 | 163543222034240 |
oct | 23060707676471 |
9 | 4573081032655 |
10 | 1312232013113 |
11 | 46657284173a |
12 | 19239ba1a135 |
13 | 96987344618 |
14 | 47725d1d957 |
15 | 24202c25578 |
hex | 131871f7d39 |
1312232013113 has 8 divisors (see below), whose sum is σ = 1499712261120. Its totient is φ = 1124756398080.
The previous prime is 1312232013097. The next prime is 1312232013121. The reversal of 1312232013113 is 3113102322131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1312232013113 - 24 = 1312232013097 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312232013133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 528473 + ... + 1704038.
It is an arithmetic number, because the mean of its divisors is an integer number (187464032640).
Almost surely, 21312232013113 is an apocalyptic number.
It is an amenable number.
1312232013113 is a deficient number, since it is larger than the sum of its proper divisors (187480248007).
1312232013113 is an equidigital number, since it uses as much as digits as its factorization.
1312232013113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2316487.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1312232013113 its reverse (3113102322131), we get a palindrome (4425334335244).
The spelling of 1312232013113 in words is "one trillion, three hundred twelve billion, two hundred thirty-two million, thirteen thousand, one hundred thirteen".
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