Base | Representation |
---|---|
bin | 1011111011110100110010… |
… | …1101010101010011011011 |
3 | 1201110111020110100112120220 |
4 | 2332331030231111103123 |
5 | 3204444144440311220 |
6 | 43524204115251123 |
7 | 2523030413651514 |
oct | 276751455252333 |
9 | 51414213315526 |
10 | 13122412041435 |
11 | 41aa202551294 |
12 | 157b2652a9aa3 |
13 | 7425907b6228 |
14 | 3351b1843a0b |
15 | 17b526291540 |
hex | bef4cb554db |
13122412041435 has 16 divisors (see below), whose sum is σ = 20995930134816. Its totient is φ = 6998596132608.
The previous prime is 13122412041341. The next prime is 13122412041449. The reversal of 13122412041435 is 53414021422131.
It is not a de Polignac number, because 13122412041435 - 213 = 13122412033243 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13122412041396 and 13122412041405.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3701457 + ... + 6320253.
It is an arithmetic number, because the mean of its divisors is an integer number (1312245633426).
Almost surely, 213122412041435 is an apocalyptic number.
13122412041435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13122412041435 is a deficient number, since it is larger than the sum of its proper divisors (7873518093381).
13122412041435 is a wasteful number, since it uses less digits than its factorization.
13122412041435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2952862.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 13122412041435 its reverse (53414021422131), we get a palindrome (66536433463566).
The spelling of 13122412041435 in words is "thirteen trillion, one hundred twenty-two billion, four hundred twelve million, forty-one thousand, four hundred thirty-five".
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