Base | Representation |
---|---|
bin | 11101110101100100000000… |
… | …010111110000111011110001 |
3 | 122012121220110002012022100100 |
4 | 131311210000113300323301 |
5 | 114144434020324240213 |
6 | 1143031312201543013 |
7 | 36432426366216423 |
oct | 3565440027607361 |
9 | 565556402168310 |
10 | 131224142024433 |
11 | 388a2934191627 |
12 | 1287414b7a4a69 |
13 | 582b4ca704b43 |
14 | 24593d4b32813 |
15 | 102869397b773 |
hex | 7759005f0ef1 |
131224142024433 has 12 divisors (see below), whose sum is σ = 189547805311488. Its totient is φ = 87481920247800.
The previous prime is 131224142024431. The next prime is 131224142024491. The reversal of 131224142024433 is 334420241422131.
131224142024433 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 2 + 4 + 1 + 4 + 202 + 443 + 3 = 666.
It is not a de Polignac number, because 131224142024433 - 21 = 131224142024431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131224142024431) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 69102993 + ... + 70976558.
It is an arithmetic number, because the mean of its divisors is an integer number (15795650442624).
Almost surely, 2131224142024433 is an apocalyptic number.
It is an amenable number.
131224142024433 is a deficient number, since it is larger than the sum of its proper divisors (58323663287055).
131224142024433 is a wasteful number, since it uses less digits than its factorization.
131224142024433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 140183644 (or 140183641 counting only the distinct ones).
The product of its (nonzero) digits is 110592, while the sum is 36.
Adding to 131224142024433 its reverse (334420241422131), we get a palindrome (465644383446564).
The spelling of 131224142024433 in words is "one hundred thirty-one trillion, two hundred twenty-four billion, one hundred forty-two million, twenty-four thousand, four hundred thirty-three".
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