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131224433 = 4327111261
BaseRepresentation
bin1111101001001…
…01001101110001
3100010220220002012
413310211031301
5232043140213
621004332305
73152250344
oct764451561
9303826065
10131224433
116808894a
1237b44095
1321256bc2
14135dc45b
15b7c14a8
hex7d25371

131224433 has 8 divisors (see below), whose sum is σ = 134783616. Its totient is φ = 127688400.

The previous prime is 131224427. The next prime is 131224441. The reversal of 131224433 is 334422131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131224433 - 24 = 131224417 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131224399 and 131224408.

It is not an unprimeable number, because it can be changed into a prime (131224463) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6023 + ... + 17283.

It is an arithmetic number, because the mean of its divisors is an integer number (16847952).

Almost surely, 2131224433 is an apocalyptic number.

It is an amenable number.

131224433 is a deficient number, since it is larger than the sum of its proper divisors (3559183).

131224433 is a wasteful number, since it uses less digits than its factorization.

131224433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11575.

The product of its digits is 1728, while the sum is 23.

The square root of 131224433 is about 11455.3233476843. The cubic root of 131224433 is about 508.1651779082.

Adding to 131224433 its reverse (334422131), we get a palindrome (465646564).

The spelling of 131224433 in words is "one hundred thirty-one million, two hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 43 271 11261 11653 484223 3051731 131224433