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131225322035 = 5139188813413
BaseRepresentation
bin111101000110110100…
…0111000001000110011
3110112201022121001110102
41322031220320020303
54122222140301120
6140141210023015
712323612555543
oct1721550701063
9415638531412
10131225322035
115071a300775
1221523117a6b
13c4b39c3962
1464cc10b323
153630701d75
hex1e8da38233

131225322035 has 8 divisors (see below), whose sum is σ = 158603267760. Its totient is φ = 104225003424.

The previous prime is 131225321989. The next prime is 131225322037. The reversal of 131225322035 is 530223522131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131225322035 - 218 = 131225059891 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131225321989 and 131225322007.

It is not an unprimeable number, because it can be changed into a prime (131225322037) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94406012 + ... + 94407401.

It is an arithmetic number, because the mean of its divisors is an integer number (19825408470).

Almost surely, 2131225322035 is an apocalyptic number.

131225322035 is a deficient number, since it is larger than the sum of its proper divisors (27377945725).

131225322035 is a wasteful number, since it uses less digits than its factorization.

131225322035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188813557.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 131225322035 its reverse (530223522131), we get a palindrome (661448844166).

The spelling of 131225322035 in words is "one hundred thirty-one billion, two hundred twenty-five million, three hundred twenty-two thousand, thirty-five".

Divisors: 1 5 139 695 188813413 944067065 26245064407 131225322035