Base | Representation |
---|---|
bin | 111101000111000001… |
… | …1000111101000010001 |
3 | 110112201210112112221112 |
4 | 1322032003013220101 |
5 | 4122230420414413 |
6 | 140142013303105 |
7 | 12324025206530 |
oct | 1721603075021 |
9 | 415653475845 |
10 | 131232201233 |
11 | 5072317a161 |
12 | 21525494a95 |
13 | c4b5261ba3 |
14 | 64ccdbc317 |
15 | 36311102a8 |
hex | 1e8e0c7a11 |
131232201233 has 16 divisors (see below), whose sum is σ = 159034596480. Its totient is φ = 105712924416.
The previous prime is 131232201229. The next prime is 131232201253. The reversal of 131232201233 is 332102232131.
It is a cyclic number.
It is not a de Polignac number, because 131232201233 - 22 = 131232201229 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131232201199 and 131232201208.
It is not an unprimeable number, because it can be changed into a prime (131232201253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 726038 + ... + 888591.
It is an arithmetic number, because the mean of its divisors is an integer number (9939662280).
Almost surely, 2131232201233 is an apocalyptic number.
It is an amenable number.
131232201233 is a deficient number, since it is larger than the sum of its proper divisors (27802395247).
131232201233 is a wasteful number, since it uses less digits than its factorization.
131232201233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1615336.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 131232201233 its reverse (332102232131), we get a palindrome (463334433364).
The spelling of 131232201233 in words is "one hundred thirty-one billion, two hundred thirty-two million, two hundred one thousand, two hundred thirty-three".
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