131233141203113 has 4 divisors (see below), whose sum is σ = 131233909488528. Its totient is φ = 131232372917700.

The previous prime is 131233141203097. The next prime is 131233141203133. The reversal of 131233141203113 is 311302141332131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131233141203113 - 2⁴ = 131233141203097 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131233141203133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 383886431 + ... + 384228132.

It is an arithmetic number, because the mean of its divisors is an integer number (32808477372132).

Almost surely, 2^{131233141203113} is an apocalyptic number.

It is an amenable number.

131233141203113 is a deficient number, since it is larger than the sum of its proper divisors (768285415).

131233141203113 is an equidigital number, since it uses as much as digits as its factorization.

131233141203113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 768285414.

The product of its (nonzero) digits is 3888, while the sum is 29.

Adding to 131233141203113 its reverse (311302141332131), we get a palindrome (442535282535244).

The spelling of 131233141203113 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, one hundred forty-one million, two hundred three thousand, one hundred thirteen".