131233204040121 has 40 divisors (see below), whose sum is σ = 197507337033600. Its totient is φ = 86834072302272.

The previous prime is 131233204040119. The next prime is 131233204040137. The reversal of 131233204040121 is 121040402332131.

131233204040121 is a `hidden beast` number, since 1 + 3 + 1 + 2 + 33 + 204 + 0 + 401 + 21 = 666.

It is not a de Polignac number, because 131233204040121 - 2¹ = 131233204040119 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131233244040121) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 58817500 + ... + 61007906.

It is an arithmetic number, because the mean of its divisors is an integer number (4937683425840).

Almost surely, 2^{131233204040121} is an apocalyptic number.

It is an amenable number.

131233204040121 is a deficient number, since it is larger than the sum of its proper divisors (66274132993479).

131233204040121 is a wasteful number, since it uses less digits than its factorization.

131233204040121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2195955 (or 2195946 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 131233204040121 its reverse (121040402332131), we get a palindrome (252273606372252).

The spelling of 131233204040121 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, two hundred four million, forty thousand, one hundred twenty-one".