13123334414353 has 4 divisors (see below), whose sum is σ = 13123342661940. Its totient is φ = 13123326166768.

The previous prime is 13123334414321. The next prime is 13123334414357. The reversal of 13123334414353 is 35341443332131.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 8947474860289 + 4175859554064 = 2991233^2 + 2043492^2 .

It is a cyclic number.

It is not a de Polignac number, because 13123334414353 - 2⁵ = 13123334414321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13123334414357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893650 + ... + 5200507.

It is an arithmetic number, because the mean of its divisors is an integer number (3280835665485).

Almost surely, 2^{13123334414353} is an apocalyptic number.

It is an amenable number.

13123334414353 is a deficient number, since it is larger than the sum of its proper divisors (8247587).

13123334414353 is an equidigital number, since it uses as much as digits as its factorization.

13123334414353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8247586.

The product of its digits is 466560, while the sum is 40.

Adding to 13123334414353 its reverse (35341443332131), we get a palindrome (48464777746484).

The spelling of 13123334414353 in words is "thirteen trillion, one hundred twenty-three billion, three hundred thirty-four million, four hundred fourteen thousand, three hundred fifty-three".