131233432210033 has 4 divisors (see below), whose sum is σ = 133457727671280. Its totient is φ = 129009136748788.

The previous prime is 131233432210003. The next prime is 131233432210057. The reversal of 131233432210033 is 330012234332131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131233432210033 - 2³³ = 131224842275441 is a prime.

It is a super-2 number, since 2×131233432210033² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131233432209977 and 131233432210004.

It is not an unprimeable number, because it can be changed into a prime (131233432210003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1112147730535 + ... + 1112147730652.

It is an arithmetic number, because the mean of its divisors is an integer number (33364431917820).

Almost surely, 2^{131233432210033} is an apocalyptic number.

It is an amenable number.

131233432210033 is a deficient number, since it is larger than the sum of its proper divisors (2224295461247).

131233432210033 is an equidigital number, since it uses as much as digits as its factorization.

131233432210033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2224295461246.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 131233432210033 its reverse (330012234332131), we get a palindrome (461245666542164).

The spelling of 131233432210033 in words is "one hundred thirty-one trillion, two hundred thirty-three billion, four hundred thirty-two million, two hundred ten thousand, thirty-three".