Base | Representation |
---|---|
bin | 10011000110001101110… |
… | …100001110001101001011 |
3 | 11122110101112022222200202 |
4 | 103012031310032031023 |
5 | 133000140120134121 |
6 | 2442514352522415 |
7 | 163546054342262 |
oct | 23061564161513 |
9 | 4573345288622 |
10 | 1312344302411 |
11 | 46662016730a |
12 | 19241155040b |
13 | 969a469b9ac |
14 | 47736bcd5d9 |
15 | 2420ca0640b |
hex | 1318dd0e34b |
1312344302411 has 4 divisors (see below), whose sum is σ = 1312350509400. Its totient is φ = 1312338095424.
The previous prime is 1312344302393. The next prime is 1312344302417. The reversal of 1312344302411 is 1142034432131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1312344302411 - 238 = 1037466395467 is a prime.
It is a super-2 number, since 2×13123443024112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1312344302417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2774741 + ... + 3213078.
It is an arithmetic number, because the mean of its divisors is an integer number (328087627350).
Almost surely, 21312344302411 is an apocalyptic number.
1312344302411 is a deficient number, since it is larger than the sum of its proper divisors (6206989).
1312344302411 is an equidigital number, since it uses as much as digits as its factorization.
1312344302411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6206988.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1312344302411 its reverse (1142034432131), we get a palindrome (2454378734542).
The spelling of 1312344302411 in words is "one trillion, three hundred twelve billion, three hundred forty-four million, three hundred two thousand, four hundred eleven".
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