13124100121 has 4 divisors (see below), whose sum is σ = 14317200144. Its totient is φ = 11931000100.

The previous prime is 13124100107. The next prime is 13124100161. The reversal of 13124100121 is 12100142131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124100121 - 2⁷ = 13124099993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13124100095 and 13124100104.

It is not an unprimeable number, because it can be changed into a prime (13124100161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 596549995 + ... + 596550016.

It is an arithmetic number, because the mean of its divisors is an integer number (3579300036).

Almost surely, 2^13124100121 is an apocalyptic number.

13124100121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13124100121 is a deficient number, since it is larger than the sum of its proper divisors (1193100023).

13124100121 is a wasteful number, since it uses less digits than its factorization.

13124100121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1193100022.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 13124100121 its reverse (12100142131), we get a palindrome (25224242252).

The spelling of 13124100121 in words is "thirteen billion, one hundred twenty-four million, one hundred thousand, one hundred twenty-one".