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13124204344403 = 174353917332989
BaseRepresentation
bin1011111011111011011110…
…0010011011010001010011
31201110122212100212222001022
42332332313202123101103
53210011332303010103
643525102022430055
72523123006200555
oct276766742332123
951418770788038
1013124204344403
1141aaa42229009
12157b68559232b
137427b7c0ca29
143353018b54d5
1517b5cd7c9138
hexbefb789b453

13124204344403 has 16 divisors (see below), whose sum is σ = 14219690617440. Its totient is φ = 12064672037376.

The previous prime is 13124204344399. The next prime is 13124204344417. The reversal of 13124204344403 is 30444340242131.

It is a cyclic number.

It is not a de Polignac number, because 13124204344403 - 22 = 13124204344399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124204344903) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39246833 + ... + 39579821.

It is an arithmetic number, because the mean of its divisors is an integer number (888730663590).

Almost surely, 213124204344403 is an apocalyptic number.

13124204344403 is a deficient number, since it is larger than the sum of its proper divisors (1095486273037).

13124204344403 is a wasteful number, since it uses less digits than its factorization.

13124204344403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 386966.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 13124204344403 its reverse (30444340242131), we get a palindrome (43568544586534).

The spelling of 13124204344403 in words is "thirteen trillion, one hundred twenty-four billion, two hundred four million, three hundred forty-four thousand, four hundred three".

Divisors: 1 17 43 731 53917 332989 916589 2318431 5660813 14318527 39413327 243414959 17953767913 305214054521 772012020259 13124204344403