Base | Representation |
---|---|
bin | 1011111011111011111100… |
… | …0101101011001001101001 |
3 | 1201110200012012021000011022 |
4 | 2332332333011223021221 |
5 | 3210012112220300001 |
6 | 43525122345542225 |
7 | 2523126105025010 |
oct | 276767705531151 |
9 | 51420165230138 |
10 | 13124331025001 |
11 | 41aaaa7793019 |
12 | 157b6bbaa4975 |
13 | 742808235671 |
14 | 33531464da77 |
15 | 17b5d999e11b |
hex | befbf16b269 |
13124331025001 has 8 divisors (see below), whose sum is σ = 15008604136704. Its totient is φ = 11242400083200.
The previous prime is 13124331024991. The next prime is 13124331025007. The reversal of 13124331025001 is 10052013342131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13124331025001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13124331025007) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 585530465 + ... + 585552878.
It is an arithmetic number, because the mean of its divisors is an integer number (1876075517088).
Almost surely, 213124331025001 is an apocalyptic number.
It is an amenable number.
13124331025001 is a deficient number, since it is larger than the sum of its proper divisors (1884273111703).
13124331025001 is a wasteful number, since it uses less digits than its factorization.
13124331025001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1171084951.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 13124331025001 its reverse (10052013342131), we get a palindrome (23176344367132).
The spelling of 13124331025001 in words is "thirteen trillion, one hundred twenty-four billion, three hundred thirty-one million, twenty-five thousand, one".
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