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1312435554313 = 13100956581101
BaseRepresentation
bin10011000110010011010…
…000010100100000001001
311122110121220001001202211
4103012103100110200021
5133000332000214223
62442531412425121
7163551243100642
oct23062320244011
94573556031684
101312435554313
11466667723204
121924380181a1
13969ba56b6c0
1447744d846c9
1524215a2dd0d
hex13193414809

1312435554313 has 4 divisors (see below), whose sum is σ = 1413392135428. Its totient is φ = 1211478973200.

The previous prime is 1312435554307. The next prime is 1312435554317. The reversal of 1312435554313 is 3134555342131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 757331581504 + 555103972809 = 870248^2 + 745053^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312435554313 - 25 = 1312435554281 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1312435554317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50478290538 + ... + 50478290563.

It is an arithmetic number, because the mean of its divisors is an integer number (353348033857).

Almost surely, 21312435554313 is an apocalyptic number.

1312435554313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1312435554313 is a deficient number, since it is larger than the sum of its proper divisors (100956581115).

1312435554313 is a wasteful number, since it uses less digits than its factorization.

1312435554313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100956581114.

The product of its digits is 324000, while the sum is 40.

The spelling of 1312435554313 in words is "one trillion, three hundred twelve billion, four hundred thirty-five million, five hundred fifty-four thousand, three hundred thirteen".

Divisors: 1 13 100956581101 1312435554313