13124404302403 has 4 divisors (see below), whose sum is σ = 13282529655528. Its totient is φ = 12966278949280.

The previous prime is 13124404302377. The next prime is 13124404302419. The reversal of 13124404302403 is 30420340442131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13124404302403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124404302203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79062676438 + ... + 79062676603.

It is an arithmetic number, because the mean of its divisors is an integer number (3320632413882).

Almost surely, 2^{13124404302403} is an apocalyptic number.

13124404302403 is a deficient number, since it is larger than the sum of its proper divisors (158125353125).

13124404302403 is an equidigital number, since it uses as much as digits as its factorization.

13124404302403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 158125353124.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 13124404302403 its reverse (30420340442131), we get a palindrome (43544744744534).

The spelling of 13124404302403 in words is "thirteen trillion, one hundred twenty-four billion, four hundred four million, three hundred two thousand, four hundred three".