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13124412500521 = 71998679793237
BaseRepresentation
bin1011111011111100001111…
…1100011110101000101001
31201110200101212120101120011
42332333003330132220221
53210012244100004041
643525134420131521
72523131114404660
oct276770374365051
951420355511504
1013124412500521
114200039781863
12157b723236ba1
1374281c09152a
143353213bbdd7
1517b5e1be4e81
hexbefc3f1ea29

13124412500521 has 8 divisors (see below), whose sum is σ = 15788766918080. Its totient is φ = 10657417669488.

The previous prime is 13124412500501. The next prime is 13124412500533. The reversal of 13124412500521 is 12500521442131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13124412500521 - 211 = 13124412498473 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124412500501) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49339896486 + ... + 49339896751.

It is an arithmetic number, because the mean of its divisors is an integer number (1973595864760).

Almost surely, 213124412500521 is an apocalyptic number.

It is an amenable number.

13124412500521 is a deficient number, since it is larger than the sum of its proper divisors (2664354417559).

13124412500521 is an equidigital number, since it uses as much as digits as its factorization.

13124412500521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98679793263.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 13124412500521 its reverse (12500521442131), we get a palindrome (25624933942652).

The spelling of 13124412500521 in words is "thirteen trillion, one hundred twenty-four billion, four hundred twelve million, five hundred thousand, five hundred twenty-one".

Divisors: 1 7 19 133 98679793237 690758552659 1874916071503 13124412500521