Base | Representation |
---|---|
bin | 11101110101110110110100… |
… | …010001011110100001010011 |
3 | 122012200211120201112002211122 |
4 | 131311312310101132201103 |
5 | 114200301402034103321 |
6 | 1143044452325432455 |
7 | 36434043045340130 |
oct | 3565666421364123 |
9 | 565624521462748 |
10 | 131244340144211 |
11 | 389004595299a8 |
12 | 12878047b6b72b |
13 | 5830399158cc8 |
14 | 245a38d46b587 |
15 | 1028e76cce8ab |
hex | 775db445e853 |
131244340144211 has 8 divisors (see below), whose sum is σ = 150003698696544. Its totient is φ = 112487523367680.
The previous prime is 131244340144153. The next prime is 131244340144213. The reversal of 131244340144211 is 112441043442131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131244340144211 - 26 = 131244340144147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131244340144213) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 635333300 + ... + 635539841.
It is an arithmetic number, because the mean of its divisors is an integer number (18750462337068).
Almost surely, 2131244340144211 is an apocalyptic number.
131244340144211 is a deficient number, since it is larger than the sum of its proper divisors (18759358552333).
131244340144211 is a wasteful number, since it uses less digits than its factorization.
131244340144211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1270887901.
The product of its (nonzero) digits is 36864, while the sum is 35.
Adding to 131244340144211 its reverse (112441043442131), we get a palindrome (243685383586342).
The spelling of 131244340144211 in words is "one hundred thirty-one trillion, two hundred forty-four billion, three hundred forty million, one hundred forty-four thousand, two hundred eleven".
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