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13124442230241 = 34374814076747
BaseRepresentation
bin1011111011111100010110…
…1101111000110111100001
31201110200110221111211001220
42332333011231320313201
53210012324202331431
643525141401245253
72523131625166356
oct276770555706741
951420427454056
1013124442230241
114200054538181
12157b731193829
137428252a0494
1433532531a62d
1517b5e4618b96
hexbefc5b78de1

13124442230241 has 4 divisors (see below), whose sum is σ = 17499256306992. Its totient is φ = 8749628153492.

The previous prime is 13124442230183. The next prime is 13124442230257. The reversal of 13124442230241 is 14203224442131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13124442230241 - 27 = 13124442230113 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (13124442210241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2187407038371 + ... + 2187407038376.

It is an arithmetic number, because the mean of its divisors is an integer number (4374814076748).

Almost surely, 213124442230241 is an apocalyptic number.

It is an amenable number.

13124442230241 is a deficient number, since it is larger than the sum of its proper divisors (4374814076751).

13124442230241 is an equidigital number, since it uses as much as digits as its factorization.

13124442230241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4374814076750.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 13124442230241 its reverse (14203224442131), we get a palindrome (27327666672372).

The spelling of 13124442230241 in words is "thirteen trillion, one hundred twenty-four billion, four hundred forty-two million, two hundred thirty thousand, two hundred forty-one".

Divisors: 1 3 4374814076747 13124442230241