Base | Representation |
---|---|
bin | 1011111011111100011000… |
… | …1101000110011001110001 |
3 | 1201110200111111220111112101 |
4 | 2332333012031012121301 |
5 | 3210012333301142040 |
6 | 43525142252500401 |
7 | 2523132054554332 |
oct | 276770615063161 |
9 | 51420444814471 |
10 | 13124450412145 |
11 | 4200059116386 |
12 | 157b733a7a701 |
13 | 742826ba6647 |
14 | 33532644a289 |
15 | 17b5e51d309a |
hex | befc6346671 |
13124450412145 has 4 divisors (see below), whose sum is σ = 15749340494580. Its totient is φ = 10499560329712.
The previous prime is 13124450412113. The next prime is 13124450412163. The reversal of 13124450412145 is 54121405442131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3076824711744 + 10047625700401 = 1754088^2 + 3169799^2 .
It is a cyclic number.
It is not a de Polignac number, because 13124450412145 - 25 = 13124450412113 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1312445041210 + ... + 1312445041219.
It is an arithmetic number, because the mean of its divisors is an integer number (3937335123645).
Almost surely, 213124450412145 is an apocalyptic number.
It is an amenable number.
13124450412145 is a deficient number, since it is larger than the sum of its proper divisors (2624890082435).
13124450412145 is an equidigital number, since it uses as much as digits as its factorization.
13124450412145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2624890082434.
The product of its (nonzero) digits is 76800, while the sum is 37.
Adding to 13124450412145 its reverse (54121405442131), we get a palindrome (67245855854276).
The spelling of 13124450412145 in words is "thirteen trillion, one hundred twenty-four billion, four hundred fifty million, four hundred twelve thousand, one hundred forty-five".
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