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13124515521001 = 75171745977853
BaseRepresentation
bin1011111011111100101000…
…0101011110000111101001
31201110200200001102101002111
42332333022011132013221
53210013001433133001
643525152540202321
72523133505150143
oct276771205360751
951420601371074
1013124515521001
114200091946655
12157b7518393a1
13742837521ab1
14335330d57c93
1517b5eac94851
hexbefca15e1e9

13124515521001 has 4 divisors (see below), whose sum is σ = 13126261506372. Its totient is φ = 13122769535632.

The previous prime is 13124515520939. The next prime is 13124515521023. The reversal of 13124515521001 is 10012551542131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12612804205401 + 511711315600 = 3551451^2 + 715340^2 .

It is a cyclic number.

It is not a de Polignac number, because 13124515521001 - 219 = 13124514996713 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13124515521031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 872981410 + ... + 872996443.

It is an arithmetic number, because the mean of its divisors is an integer number (3281565376593).

Almost surely, 213124515521001 is an apocalyptic number.

It is an amenable number.

13124515521001 is a deficient number, since it is larger than the sum of its proper divisors (1745985371).

13124515521001 is an equidigital number, since it uses as much as digits as its factorization.

13124515521001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1745985370.

The product of its (nonzero) digits is 6000, while the sum is 31.

The spelling of 13124515521001 in words is "thirteen trillion, one hundred twenty-four billion, five hundred fifteen million, five hundred twenty-one thousand, one".

Divisors: 1 7517 1745977853 13124515521001