131246565642131 has 4 divisors (see below), whose sum is σ = 138966951856392. Its totient is φ = 123526179427872.

The previous prime is 131246565642091. The next prime is 131246565642149.

131246565642131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131246565642131 - 2¹⁸ = 131246565379987 is a prime.

It is a super-2 number, since 2×131246565642131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131246565642131.

It is not an unprimeable number, because it can be changed into a prime (131246565642191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3860193107105 + ... + 3860193107138.

It is an arithmetic number, because the mean of its divisors is an integer number (34741737964098).

Almost surely, 2^{131246565642131} is an apocalyptic number.

131246565642131 is a deficient number, since it is larger than the sum of its proper divisors (7720386214261).

131246565642131 is an equidigital number, since it uses as much as digits as its factorization.

131246565642131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7720386214260.

The product of its digits is 3110400, while the sum is 50.

The spelling of 131246565642131 in words is "one hundred thirty-one trillion, two hundred forty-six billion, five hundred sixty-five million, six hundred forty-two thousand, one hundred thirty-one".