13125340200435 has 16 divisors (see below), whose sum is σ = 21296326636800. Its totient is φ = 6901587334880.

The previous prime is 13125340200419. The next prime is 13125340200461. The reversal of 13125340200435 is 53400204352131.

It is not a de Polignac number, because 13125340200435 - 2⁴ = 13125340200419 is a prime.

It is a super-3 number, since 3×13125340200435³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13125340200396 and 13125340200405.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6162130485 + ... + 6162132614.

It is an arithmetic number, because the mean of its divisors is an integer number (1331020414800).

Almost surely, 2^{13125340200435} is an apocalyptic number.

13125340200435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13125340200435 is a deficient number, since it is larger than the sum of its proper divisors (8170986436365).

13125340200435 is a wasteful number, since it uses less digits than its factorization.

13125340200435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12324263178.

The product of its (nonzero) digits is 43200, while the sum is 33.

Adding to 13125340200435 its reverse (53400204352131), we get a palindrome (66525544552566).

The spelling of 13125340200435 in words is "thirteen trillion, one hundred twenty-five billion, three hundred forty million, two hundred thousand, four hundred thirty-five".