1312544022313 has 4 divisors (see below), whose sum is σ = 1315817199828. Its totient is φ = 1309270844800.

The previous prime is 1312544022311. The next prime is 1312544022323. The reversal of 1312544022313 is 3132204452131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 802022340249 + 510521682064 = 895557^2 + 714508^2 .

It is a cyclic number.

It is not a de Polignac number, because 1312544022313 - 2¹ = 1312544022311 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1312544022311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1636588156 + ... + 1636588957.

It is an arithmetic number, because the mean of its divisors is an integer number (328954299957).

Almost surely, 2^{1312544022313} is an apocalyptic number.

It is an amenable number.

1312544022313 is a deficient number, since it is larger than the sum of its proper divisors (3273177515).

1312544022313 is an equidigital number, since it uses as much as digits as its factorization.

1312544022313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3273177514.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1312544022313 its reverse (3132204452131), we get a palindrome (4444748474444).

The spelling of 1312544022313 in words is "one trillion, three hundred twelve billion, five hundred forty-four million, twenty-two thousand, three hundred thirteen".