Base | Representation |
---|---|
bin | 1011111100000000000101… |
… | …1101010010011011001011 |
3 | 1201110210001210110222101121 |
4 | 2333000001131102123023 |
5 | 3210021402243331220 |
6 | 43525425043500111 |
7 | 2523165515351104 |
oct | 277000135223313 |
9 | 51423053428347 |
10 | 13125444511435 |
11 | 4200519279943 |
12 | 157b970987637 |
13 | 742954b28a89 |
14 | 3353bc49d3ab |
15 | 17b6525eaeaa |
hex | bf0017526cb |
13125444511435 has 8 divisors (see below), whose sum is σ = 15750553111776. Its totient is φ = 10500342477120.
The previous prime is 13125444511409. The next prime is 13125444511463. The reversal of 13125444511435 is 53411544452131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13125444511435 - 27 = 13125444511307 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13125444511391 and 13125444511400.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5937370 + ... + 7842400.
It is an arithmetic number, because the mean of its divisors is an integer number (1968819138972).
Almost surely, 213125444511435 is an apocalyptic number.
13125444511435 is a deficient number, since it is larger than the sum of its proper divisors (2625108600341).
13125444511435 is a wasteful number, since it uses less digits than its factorization.
13125444511435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3283013.
The product of its digits is 576000, while the sum is 43.
Adding to 13125444511435 its reverse (53411544452131), we get a palindrome (66536988963566).
The spelling of 13125444511435 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-four million, five hundred eleven thousand, four hundred thirty-five".
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