13125513541433 has 4 divisors (see below), whose sum is σ = 13897602573300. Its totient is φ = 12353424509568.

The previous prime is 13125513541421. The next prime is 13125513541471. The reversal of 13125513541433 is 33414531552131.

13125513541433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8851321163689 + 4274192377744 = 2975117^2 + 2067412^2 .

It is a cyclic number.

It is not a de Polignac number, because 13125513541433 - 2¹⁰ = 13125513540409 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13125513541633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 386044515908 + ... + 386044515941.

It is an arithmetic number, because the mean of its divisors is an integer number (3474400643325).

Almost surely, 2^{13125513541433} is an apocalyptic number.

It is an amenable number.

13125513541433 is a deficient number, since it is larger than the sum of its proper divisors (772089031867).

13125513541433 is an equidigital number, since it uses as much as digits as its factorization.

13125513541433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 772089031866.

The product of its digits is 324000, while the sum is 41.

The spelling of 13125513541433 in words is "thirteen trillion, one hundred twenty-five billion, five hundred thirteen million, five hundred forty-one thousand, four hundred thirty-three".