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131267315163 = 343755771721
BaseRepresentation
bin111101001000000100…
…1000100010111011011
3110112211020121112012110
41322100021010113123
54122313413041123
6140145310043403
712324632524515
oct1722011042733
9415736545173
10131267315163
1150740a82836
12215351a9563
13c4bc60776a
1464d391cbb5
153634249493
hex1e902445db

131267315163 has 4 divisors (see below), whose sum is σ = 175023086888. Its totient is φ = 87511543440.

The previous prime is 131267315131. The next prime is 131267315167. The reversal of 131267315163 is 361513762131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131267315163 - 25 = 131267315131 is a prime.

It is a super-2 number, since 2×1312673151632 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131267315167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21877885858 + ... + 21877885863.

It is an arithmetic number, because the mean of its divisors is an integer number (43755771722).

Almost surely, 2131267315163 is an apocalyptic number.

131267315163 is a deficient number, since it is larger than the sum of its proper divisors (43755771725).

131267315163 is an equidigital number, since it uses as much as digits as its factorization.

131267315163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43755771724.

The product of its digits is 68040, while the sum is 39.

The spelling of 131267315163 in words is "one hundred thirty-one billion, two hundred sixty-seven million, three hundred fifteen thousand, one hundred sixty-three".

Divisors: 1 3 43755771721 131267315163