Base | Representation |
---|---|
bin | 11101110110101010101010… |
… | …100001110001110100001001 |
3 | 122012220011021112110210021011 |
4 | 131312222222201301310021 |
5 | 114202204410333021413 |
6 | 1143130220434043521 |
7 | 36441053451564202 |
oct | 3566525241616411 |
9 | 565804245423234 |
10 | 131300011220233 |
11 | 38922027393339 |
12 | 128869a41195a1 |
13 | 58356cbaaa6cb |
14 | 245cd510285a9 |
15 | 102a63448833d |
hex | 776aaa871d09 |
131300011220233 has 8 divisors (see below), whose sum is σ = 133676653125600. Its totient is φ = 128928409914528.
The previous prime is 131300011220221. The next prime is 131300011220267. The reversal of 131300011220233 is 332022110003131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131300011220233 - 29 = 131300011219721 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131300011220293) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1260097348 + ... + 1260201541.
It is an arithmetic number, because the mean of its divisors is an integer number (16709581640700).
Almost surely, 2131300011220233 is an apocalyptic number.
It is an amenable number.
131300011220233 is a deficient number, since it is larger than the sum of its proper divisors (2376641905367).
131300011220233 is an equidigital number, since it uses as much as digits as its factorization.
131300011220233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2520299831.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 131300011220233 its reverse (332022110003131), we get a palindrome (463322121223364).
The spelling of 131300011220233 in words is "one hundred thirty-one trillion, three hundred billion, eleven million, two hundred twenty thousand, two hundred thirty-three".
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