Base | Representation |
---|---|
bin | 10011000110110100111… |
… | …101011100000111100001 |
3 | 11122112002022002012201222 |
4 | 103012310331130013201 |
5 | 133003011230430423 |
6 | 2443103452504425 |
7 | 163601250416303 |
oct | 23066475340741 |
9 | 4575068065658 |
10 | 1313001030113 |
11 | 466927940583 |
12 | 19257547b115 |
13 | 96a7a769c76 |
14 | 4779a101973 |
15 | 2424a4cc3c8 |
hex | 131b4f5c1e1 |
1313001030113 has 16 divisors (see below), whose sum is σ = 1338257203200. Its totient is φ = 1287944421120.
The previous prime is 1313001030097. The next prime is 1313001030127. The reversal of 1313001030113 is 3110301003131.
It is a cyclic number.
It is not a de Polignac number, because 1313001030113 - 24 = 1313001030097 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1313001030091 and 1313001030100.
It is not an unprimeable number, because it can be changed into a prime (1313001032113) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 88237808 + ... + 88252686.
It is an arithmetic number, because the mean of its divisors is an integer number (83641075200).
Almost surely, 21313001030113 is an apocalyptic number.
It is an amenable number.
1313001030113 is a deficient number, since it is larger than the sum of its proper divisors (25256173087).
1313001030113 is a wasteful number, since it uses less digits than its factorization.
1313001030113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21472.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1313001030113 its reverse (3110301003131), we get a palindrome (4423302033244).
The spelling of 1313001030113 in words is "one trillion, three hundred thirteen billion, one million, thirty thousand, one hundred thirteen".
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