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131300111011 = 1300710094573
BaseRepresentation
bin111101001001000011…
…0001011001010100011
3110112220112022201122111
41322102012023022203
54122400312023021
6140152441020151
712325511346316
oct1722206131243
9415815281574
10131300111011
1150758542843
1221544184657
13c4c634b1a4
1464d801897d
1536370768e1
hex1e9218b2a3

131300111011 has 4 divisors (see below), whose sum is σ = 131310218592. Its totient is φ = 131290003432.

The previous prime is 131300110969. The next prime is 131300111023. The reversal of 131300111011 is 110111003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131300111011 - 27 = 131300110883 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131300110982 and 131300111000.

It is not an unprimeable number, because it can be changed into a prime (131300111081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5034280 + ... + 5060293.

It is an arithmetic number, because the mean of its divisors is an integer number (32827554648).

Almost surely, 2131300111011 is an apocalyptic number.

131300111011 is a deficient number, since it is larger than the sum of its proper divisors (10107581).

131300111011 is a wasteful number, since it uses less digits than its factorization.

131300111011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10107580.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 131300111011 its reverse (110111003131), we get a palindrome (241411114142).

The spelling of 131300111011 in words is "one hundred thirty-one billion, three hundred million, one hundred eleven thousand, eleven".

Divisors: 1 13007 10094573 131300111011